4s^2-192=0

Solution for 4s^2-192=0 equation:

4s^2-192=0

a = 4; b = 0; c = -192;
Δ = b2-4ac
Δ = 02-4·4·(-192)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*4}=\frac{0-32\sqrt{3}}{8}
=-\frac{32\sqrt{3}}{8}
=-4\sqrt{3}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*4}=\frac{0+32\sqrt{3}}{8}
=\frac{32\sqrt{3}}{8}
=4\sqrt{3}
$